-2x^2-9x+12=0

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Solution for -2x^2-9x+12=0 equation: 



-2x^2-9x+12=0

a = -2; b = -9; c = +12;
Δ = b2-4ac
Δ = -92-4·(-2)·12
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{177}}{2*-2}=\frac{9-\sqrt{177}}{-4}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{177}}{2*-2}=\frac{9+\sqrt{177}}{-4}
$

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